find the perimeter of the rectangle whose length is 40cm and diagonal is 41cm.
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Answered by
4
Diognol^2=l^2+b^2
41×41=40×40+b^2
B=9
Perimeter=2(l+b)
=2(40+9)
=2(49)
=98cm
41×41=40×40+b^2
B=9
Perimeter=2(l+b)
=2(40+9)
=2(49)
=98cm
Answered by
1
the answer is 98 cm
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