Math, asked by jyoti2294, 1 year ago

find the perimeter of triangle abc. a= 4 2/3. b=3/4.c=2 3/5

Answers

Answered by mysticd
1
Given In ∆ABC ,

a = 4 2/3 = 14/3 ,

b = 3/4 ,

c = 2 3/5 = 13/5

Perimeter = a + b + c

= 14/3 + 3/4 + 13/5

LCM( 3,4,5) = 60

= ( 14 × 20 + 3 × 15 + 13 × 12 )/60

= ( 280 + 45 + 156 )/60

= 481/60

= 1 8/60

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Answered by sp0004207
0

Answer:

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