Question

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For motion on a straight line path with constant acceleration , the ratio of the magnitude of displacement to the distance covered is

Answer 1

For motion on a straight line path with constant acceleration, the ratio of magnitude of the displacement to the distance covered is?

Answer

Suppose

Displacement Vector = 2 i+0 j+ 0 k

Accleration = Cons
Displacement: Shortest Distance between Final and Initial position=D
Distance: Total length of path travelled=d
Since Path is Straight:
Displacement(D)= Distance(d)==>D/d=1====Logial Way

OR

Since this is a straight line path,
Therefore,
Distance= Magnitude of Displacement vector= (2^2 + 0 + 0 )^0.5=2
Dispalcement/Distance=2/2=1 (Mathematical Way)

thanks