Find the perpendicular distance from a to bc if a to b =32cm b to c =43cm
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0
Answer:
We have to find a perpendicular distance AP
Now
AB
=(2,1,−2)−(1,4,−2)=(1,−3,0)
AC
=(0,−5,1)−(1,4,−2)=(−1,−9,3)
AB
×
AC
∣
∣
∣
∣
∣
∣
∣
∣
i
1
−1
j
−3
−9
k
0
3
∣
∣
∣
∣
∣
∣
∣
∣
=−9i−3j−12k
∣
AB
×
AC
∣=
(−9)
2
+(−3)
2
+(−12)
2
=3
26
units
Area of Δ=
2
1
∣
AB
×
AC
∣=
2
3
26
sq.units
Now
BC
=(0,−5,1)−(2,1,−2)
=(−2,−6,3),∣
BC
∣=
(2)
2
+(6)
2
+3
2
=7 units
=
2
1
×7×AP=
2
3
26
∴Ap=
7
3
26
units
Answered By
toppr
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