Question

find the point of intersection of the straight lines are 4 x + 8 Y - 1 equal to zero 2 x minus y + 1 equal to zero​

Answer 1

Answer:

$4x + 8y - 1 = 0 \: .....eq(i) \\ \: \: 2x - y + 1 = 0 .....eq(ii)\\ multipying \: eq.(ii) \: with \: 2 \\ 2(2x - y + 1) \\ 4x - 2y + 2.....eq(iii) \\ using \: elimination \: method \: on \: eq(i) \: and \: eq(iii) \\ \: {subtracting \: them} \\ 4x + 8y - 1 - (4x - 2y + 2) = 0 \\ 4x + 8y - 1 - 4x + 2y - 2 = 0 \\ 10y - 3 = 0 \\ y = \frac{3}{10} \\ using \: x \: to \: find \: y \\ 2( \frac{3}{10}) - y = - 1 \\ \frac{6}{10} - y = - 1 \\ - y = - 1 - \frac{6}{10} \\ - y = \frac{ - 10 - 6}{10} \\ y = \frac{8}{5}$

Answer 2

Answer:

dinchak pooja

Step-by-step explanation:

dhipuk jhipuk phakhaphak