Question

Find the point of intersection of Y-axis and the perpendicular bisector of (2,-3) and (-4,1).

Plzz answer this...

Answer 1

hope this helps........

Answer 2

Answer:

(0, 1/2)

Step-by-step explanation:

As the point P is on the Y-axis, so the point is P(0,y).

Given that point P lies on perpendicular bisector of line segment joining the points A(2,-3) and B(-4,1). therefore, P is equidistant from points A and B.

⇒ AP = BP

On squaring both sides, we get

⇒ AP² = BP²

⇒ (0 - 2)² + (y + 3)² = (0 + 4)² + (y - 1)²

⇒ 4 + y² + 9 + 6y = 16 + y² + 1 - 2y

⇒ y² + 6y + 13 = y² - 2y + 17

⇒ 8y = 4

⇒ y = 4/8

⇒ y = 1/2.

Hence, the point P is (0,1/2).

Hope it helps!