Question

find the point on x axis which is equidistant from the point 5, 4 and
- 2, 3

Answer 1

hope my answer would help you

regard madhu@

Answer 2

Let point be(x,0)
then,
by the distance formula (hope u know about it)
After squaring both sides
We get,
(x-5)^2 + (0-4)^2. =( x+2)^2 + (0-3)^2
x^2+ 25 +. 10x + 16 = x^2+ 4 +4x + 9
25 -10x +16 = 4 + 4x + 9
28 = 14x
x =28/14
x = 2
so, point is (2,0)
hope it helps
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