find the point where the graph of the linear equation 7-2x+4y=0 cuts the y axis
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Answered by
19
Answer:
the graph of the linear equation 7-2x+4y=0 cuts the y axis at (0 , -7/4)
Step-by-step explanation:
Find the point where the graph of the linear equation 7-2x+4y=0 cuts the y axis
Graph cut the y axis at x = 0
7 - 2x + 4y = 0
Putting x = 0
=> 7 - 2(0) + 4y = 0
=> 4y = -7
=> y = -7/4
the graph of the linear equation 7-2x+4y=0 cuts the y axis at (0 , -7/4)
Answered by
3
Answer :
Given:
find the point where the graph of the linear equation 7 - 2x + 4y= 0 cuts the y-axis
=> 7 - 2x + 4y = 0
=> y = mx + c
=> 4y = 2x - 7
=> 4 = 2 / 4x - 7 / 4
=> y = mx + c
=> c = 7 / 4
=> 7 = 2x + 4y = 0
=> [ 0, 7/4 ] = y - axis.
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