Question

Find the points on the curve y = x^3 − 2x^2 − x

where the tangents are parallel to 3x−y + 1 = 0.​

Answer 1

Answer:

2/3 and 2 (these are x coordinates, Y coordinates can be found out by substituting these x coordinates in the curve)

Step-by-step explanation:

1. Differentiate the curves, that gives the slope of tangent for the corresponding value of x
2. Substitute dy/dx as 3(slope of the line given).
3. U will get a quadratic equation, solve to get the x coordinates.