find the position and nature of an image of an object 5 cm high and 10cm in front of a convex lens of focal length 6cm
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Given that, an object 5 cm high and 10 cm in front of a convex lens of focal length 6 cm.
We have to find the the position and nature of an image.
Form above data we have; height of object (h) is 5 cm, image distance (u) form the lens is -10 cm and focal length (f) is 6 cm.
Using Lens formula:
1/f = 1/v - 1/u
Substitute the known values,
1/6 = 1/v - 1/(-10)
1/6 = 1/v + 1/10
1/v = 1/6 - 1/10
1/v = 1/2(1/3 - 1/5)
1/v = 1/2(2/15)
1/v = 1/15
v = +15
Therefore, the image distance from the lens is +15 cm. (Positive sign means image is formed on the right side of the lens.) Image is formed behind the lens.
Now, using Magnification formula:
m = v/u = h'/h
Substitute the values,
m = 15/(-10)
m = -1.5
Image formed will be real and inverted.
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