Math, asked by leuvajaimin123, 5 months ago

find the prime factorisation of 1980



Answers

Answered by Bobbysingh20152007
6

Answer:

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Answered by ananditanunes65
0

Answer:

Let's start by dividing 1,980 by 2

1,980 ÷ 2 = 990 - No remainder! 2 is one of the factors!

990 ÷ 2 = 495 - No remainder! 2 is one of the factors!

495 ÷ 2 = 247.5 - There is a remainder. We can't divide by 2 evenly anymore. Let's try the next prime number

495 ÷ 3 = 165 - No remainder! 3 is one of the factors!

165 ÷ 3 = 55 - No remainder! 3 is one of the factors!

55 ÷ 3 = 18.3333 - There is a remainder. We can't divide by 3 evenly anymore. Let's try the next prime number

55 ÷ 5 = 11 - No remainder! 5 is one of the factors!

11 ÷ 5 = 2.2 - There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number

11 ÷ 7 = 1.5714 - This has a remainder. 7 is not a factor.

11 ÷ 11 = 1 - No remainder! 11 is one of the factors!

The orange divisor(s) above are the prime factors of the number 1,980. If we put all of it together we have the factors 2 x 2 x 3 x 3 x 5 x 11 = 1,980. It can also be written in exponential form as 22 x 32 x 51 x 111.

Factor Tree

Another way to do prime factorization is to use a factor tree. Below is a factor tree for the number 1,980.

(Check the attachment)

Hope this helps you

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