Question

find the principal for which simple interest for 4yrs at 8% is 585 less than simple interest for 3.5 years at 11%​

Answer 1

Answer:

Ans: Rs. 9000

Ans: Rs. 9000P

Ans: Rs. 9000P×

Ans: Rs. 9000P×11

Ans: Rs. 9000P×11×

Ans: Rs. 9000P×11×3.5

Ans: Rs. 9000P×11×3.5100

Ans: Rs. 9000P×11×3.5100−

Ans: Rs. 9000P×11×3.5100−P

Ans: Rs. 9000P×11×3.5100−P×

Ans: Rs. 9000P×11×3.5100−P×8

Ans: Rs. 9000P×11×3.5100−P×8×

Ans: Rs. 9000P×11×3.5100−P×8×4

Ans: Rs. 9000P×11×3.5100−P×8×4100

Ans: Rs. 9000P×11×3.5100−P×8×4100=

Ans: Rs. 9000P×11×3.5100−P×8×4100=585

Ans: Rs. 9000P×11×3.5100−P×8×4100=585

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500 ⇒

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500 ⇒P

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500 ⇒P=

Ans: Rs. 9000P×11×3.5100−P×8×4100=585 ⇒38.5P−32P=58500 ⇒6.5P=58500 ⇒P=9000

Step-by-step explanation:

we

Answer 2

Answer:

9000rs

firstly solve equation 1 and 2

find value of P

then .

SI = 6.5/100

585=6.5/100P

58500=6.5P

P=58500/6.5

P=9000