find the probability of getting a sum of 7 or 8 in throwing a die twice
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the probability of getting a sum 7 or 8 in throwing a twice dice are
4/36=1/9
4/36=1/9
aman26660th:
wrong answer
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Hey friend
Here is your answer
Probability of A or B =
Probability of A + probability of B
Total no of event = 6×6=36
(1,2). (3,4) ... Any no van came
Probability of 7
P(7) == ( 1,6) (2,5) (3,4) (4,3) (5,2 ) (6,1)
Total 6 events
P(7) = 6/36
P(8) == (2,6) (3,5) (4,4) (5,3) (6,2)
P(8) = 5/36
P of (A OR B) = 6/36 + 5/36 = 11/36
Hope it will help you !!
Here is your answer
Probability of A or B =
Probability of A + probability of B
Total no of event = 6×6=36
(1,2). (3,4) ... Any no van came
Probability of 7
P(7) == ( 1,6) (2,5) (3,4) (4,3) (5,2 ) (6,1)
Total 6 events
P(7) = 6/36
P(8) == (2,6) (3,5) (4,4) (5,3) (6,2)
P(8) = 5/36
P of (A OR B) = 6/36 + 5/36 = 11/36
Hope it will help you !!
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