find the probability that a leap year selected at a random will contain 53 Sundays
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Answered by
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2/7
Step-by-step explanation:
the seven days repeat 52 times in 364 days. in a leap year, two days remain. either of the two days (365th or 366th ) can be suday. So there are two possibilities in favour of the event. Further a day can have any of the seven days. the other day will have corresponding next day. hence sample space is 7.
hence the probability is 2/7
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