Question

find the probability that a non leap year selected at random will have 53 Sundays​

Answer 1

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7

Answer 2

Answer:1/7

Step-by-step explanation:as we know that a non leap year has 52 weeks .

This can be prooved by 365÷7

We divided 365 by 7 as there are 365 days in a year and 7 days in a week.

Then we will be left with remainder 1 and quotient 52

So clearly there will be 52 weeks with one extra day .

Now that day can be any one day of the week i.e 7 days (mon. Tues. Wed. Thurs. Fri. Sat. Sun.)

So total possible outcomes = 7

Favourable outcome = 1 (Sunday comes one time in a week)

So probability = favourable outcome/total outcomes

So 1/7 is the correct answer

Hope it helps