Find the product of (2a - b + c) (4a² + b2 + c2 + 2ab + bc - 2ca).
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1
Answer:
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WE need to find value of (2a+b+c)(4a
2
+b
2
+c
2
−2ab−bc−2ac)
(2a+b+c)[(2a)
2
+(b)
2
+(c)
2
−(2a)(b)−(b)(c)−(2a)(c)]
(x+y+z)(x
2
+y
2
+z
2
−xy−yz−zx=x
3
+y
3
+z
3
−3xyz
Compairing both, we get
x=2ay=b and z=c
Then (2a+b+c)[(2a)
2
+(b)
2
+(c)
3
−(2a)(b)−(b)(c)−(2a)(c)]
= (2a)
3
+b
3
+c
3
−3(2a)(b)(c)
= 8a
3
+b
3
+c
3
−6abc
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0
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