find the product of : -8/3a²bc³ × 7/4a²bc³
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Heya friend,
Here is the answer you were looking for:

We know that,


Hope this helps!!
If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.
@Mahak24
Thanks...
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Here is the answer you were looking for:
We know that,
Hope this helps!!
If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.
@Mahak24
Thanks...
☺☺
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