Question

find the product of following using sutibble identities, (2x+1)/3 (2x-1)/3​

Answer 1

Answer:

(2x+1)/3*(2x-1)/3=(2x+1)(2x-1)/3=2x^2-1/2

2x^2-1=2

2x^2-1-2=0

And u can solve this quadratic problem

Answer 2

we can write it as

$\frac{(2x + 1)(2x - 1)}{9}$

now we know identity

$(a + b)(a - b) = {a}^{2} - {b}^{2}$

so now

we can write the equation as

$\frac{ {(2x)}^{2} - {1}^{2} }{9}$

so the answer will be

$\frac{ {4x }^{2} - 1 }{9}$

hope this helps...