prove that √3 is an irrational number
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let under root 3 is rational number
assume under root 3 =a/b
a and b are co-brime numbers
by squaring both side
3=asquare/bsquare
so a square=3b square
so a square is divisible by 3
hence a also divisible by 3
a/3=c
squaring both side
a square /9 = c
3b square=9c square
now b square =3 c square
bsquare is also divisible by 3
hence b is also divisible by 3
so our assumptions is wrong
and hence under root 3 is irrational number
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