Question

find the product of zeroes of 2x
${2x}^{2} - kx + 6$

Answer 1

Heyaa folk !!

We have ,

${2x}^{2} - kx + 6 \: where \: \\ \: a = 2 \: \: b = - k \: \: c = 6 \\ let \: \alpha \: and \: \beta \: be \: th \: zeroes \: of \: that \: poynomial \ \\ then \: product \:of \: zeroes \: \\ ( \alpha \beta ) = \frac{c}{a} \\ \\ = \frac{6}{2} \\ = 3$
Hope this helps u!!