Question

find the product of zeroes of the quadric polynomial 3x^2+5x-2
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Answer 1

Answer:

$3x { }^{2} - 6x + 1x - 2 \\ 3x(x - 2) + 1(x - 2) \\ (x - 2)(3x + 1)$

x-2 = 0

3x +1= 0

Answer 2

3x²+5x-2=0

3x²+6x-1x-2=0

3x(x+2)-1(x+2)=0

3x-1=0

x+2=0

x=(1/3 , -2)