Question

In the given triangle find the mentioned angleADparallel BE​

Answer 1

Answer:

Y=132 degree and x =70 degree

Step-by-step explanation:

Y=180-48

=132 degree

If a pair of parallel line joining by a transversal.

( Adjacent angles on the same side of the transversal are add up to 180)

X+62=Y

X=y-62

X=132-62

X=70 degree

( exterior angle of triangle equal to the sum of the two opposite interior angles of the triangle)

Answer 2

Answer:

if AD is parallel to to BE then angle ACB is equals to 48 degree (alternate interior angle)

angle ACB+angle BAC +angle ABC =180°(angle sum property)

48°+62°+angle x=180°

110° +angle x= 180°

x= 180°-110°

x= 70°

now ,

angle ABC+angle BAC = angle ACE (exterior angle property)

70°+62°= y

132°=y

y=132°,x=70°

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