Find the Pythagorean triplet in which one member is 14
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Answer:
Let us assume 2 m=14 therefore m=7
Now m ^2 +1=7 ^2 +1=49+1=50
And m ^2 −1=7 ^2 −1=49−1=48
Test : 14 ^2 +48 ^2 =196+1304=2500=50 ^2
Hence the triplet is 14,48 and 50 Answer
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