Question

find the Pythagorean triplet of 18​

Answer 1

$\huge\bold{ANSWER~:}$

Pythagoras triplets are in form :-

$\bold{1m \: and \: {m}^{2} + 1 \: and \: {m}^{2} - 1}$

Here 1 number '2m' is 18

$2m = 18 \\ \\ m = 9$

2nd,

${m}^{2} + 1 \\ \\ = 81 + 1 \\ \\ = 82$

3rs

$= {m}^{2} - 1 \\ \\ = 81 - 1 \\ \\ = 80$

Than Pythagoras triplets became

( 18 , 82 , 80 )

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