Question

Find the Pythagorean triplets, one of whose members is:
(1) 82​

Answer 1

If we take m2 + 1 = 18,

m2 = 17

The value of m will not be an integer.

If we take m2 − 1 = 18, then m2 = 19

Again the value of m is not an integer.

Let 2m =18

m = 9

Thus, m2 − 1 = 81 − 1 = 80 and m2 + 1 = 81 + 1 = 82

the Pythagorean triplet is 18, 80, and 82.