Question

find the quadratic equations the value of k is 3 x squared minus k √3 + 4 is equal to zero have equal roots

Answer 1

Answer:

+/-4

Step-by-step explanation:

Ax^2 + bx + c = 0

For equal roots

b^2 = 4ac

3k^2 = 4×3×4

K^2 = 16

k = +/-4

Answer 2

Answer:

Step-by-step explanation:

3x square -k root 3 +4

a b c

Compare

a=3

b=-k root 3

c=4

Since equation have equal roots

So D=0

Using discriminat formula

D=b square-4ac

O=(-k root 3)sq.-4×3×4

0=k sq. 3-48

48=k sq. 3

16 =k sq.

+/_ 4=k

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