Find the quadratic polynomial whose one of the two zeroes is 2 route3
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Answered by
4
Hi friend!!
Quadratic polynomial whose zeros are 2√3 and -2√3 is
(x-2√3)(x+2√3)
=x²+2√3x-2√3x-12
=x²-12
I hope this helps you ;)
anshika780:
it is 2 route 3 not 2+root 3
Answered by
3
Answer:
x2-x-12
Step-by-step explanation:
one of the zero which is given is 2 root 3
alpha -(2 route 3)
beta -(-2 route 3)
**sum of the zeros
•alpha + beta =-b/a
•2 route 3+(-2 route 3)=-b/a
-b/a will equal to 1_________(1)
**product of the zeros
(2 route 3)(-2 route 3) =c/a
-12=c/a________(2)
b=-1, a=1, c=-12
to form the equation
** ax2 +bx+c
x2 - x - 12
answer is---- x2-x-12
hope it helps you if yes then please math it as brainliest
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