Question

find the quadratic polynomial whose sum and product of its zeros respectively are option (1)3 and 8 option(2) 1 by 4 and minus 2 option (3)2 and minus 4​

Answer 1

Answer:

Step-by-step explanation:

polynomial

(i)

⇒ x²-(sum of zeroes)x +(product of zeroes)

⇒x²-3x+8=0

(ii)

⇒ x²-(sum of zeroes)x +(product of zeroes)

⇒x²-1/4x -2

⇒4x²-x-8=0

(iii)

⇒ x²-(sum of zeroes)x +(product of zeroes)

⇒x²-2x-4

⇒x²-2x-4=0

Answer 2

let alpha and Beta are the zeros of the quadratic equation ax^2+bx+c=0

then equation will be

$x { }^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

1. alpha=3

beta=8

then equation

x^2-(3+8)x+3×8=0

x^2-11x+24=0

hope it will help you