Math, asked by mustafa72, 11 months ago

find the quadratic polynomial whose sum and product of its zeroes are 2/3 and -1/3 respectively​

Answers

Answered by Anonymous
11

HELLO

x² - (sum of zeros)x + (product of Zeros) =0

 {x}^{2}  -  \frac{2}{3} x \:   - \frac{1 }{3}  = 0 \\  \\ 3 {x}^{2}  - 2x \:  - 1 = 0


mustafa72: it is not correct i want full solution
Anonymous: Ok
Answered by hinaguptagracy
9

Sum of zeroes = 2/3

product of zeroes = -1/3

So by formula of quadratic polynomial:-

x^2-(Sum of zeroes)x+(Product of zeroes)

x^2-2/3x-1/3

3x^2-2x-1.

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