# find the quadratic polynomial whose zeroes are -2 and -5.Verify the relationship between their zeroes and coefficients

## Answers

Answered by

11

let the zeros be alpha and beta

then,

f(x) = x^2 - (alpha+ beta)x +alpha•beta

=x^2 -{-2+(-5)}x + (-2)(-5)

= x^2 +7x + 10

Verification:

sum of zeros = -b/a

=> -2 + (-5) = -7/1

=> -7 = -7

L.H.S = R.H.S

Product of zeros = c/a

=> (-2)(-5) = 10/1

=> 10 = 10

L.H.S = R.H.S

Hope it helps!!!

If it does, plz mark it as brainliest..

then,

f(x) = x^2 - (alpha+ beta)x +alpha•beta

=x^2 -{-2+(-5)}x + (-2)(-5)

= x^2 +7x + 10

Verification:

sum of zeros = -b/a

=> -2 + (-5) = -7/1

=> -7 = -7

L.H.S = R.H.S

Product of zeros = c/a

=> (-2)(-5) = 10/1

=> 10 = 10

L.H.S = R.H.S

Hope it helps!!!

If it does, plz mark it as brainliest..

Answered by

3

given :-

zeroes = -2 and -5

now ,

sum of zeroes = -2 +( -5 ) = -7 = coefficient of x / coefficient of x^2 = -b/ a

product of zeroes = -2 * -5 = -10 = constant term / coefficient of x^2 = c /a

so , the equation will be

x^2 + 7x - 10

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