# The sum of 2 numbers is 80 & the greater number exceeds twice the smaller number by 11. Find the numbers.

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__Solution____ ____:__

Let, the two numbers are **x** and **y**, x > y

Given that,

x + y = 80 .....(i)

x = 2y + 11 .....(ii)

Putting x = 2y + 11 in (i), we get

2y + 11 + y = 80

⇒ 3y = 80 - 11 = 69

⇒ **y = 23**

Then,** x** = 2 (23) + 11 = 46 + 11 **= 57**

∴ the two numbers are **5****7** and **23**

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