Question

Find the quadratic polynomial whose zeros are 1/6 and -1/3

Answer 1

Answer:

x^2 + 1/6*x -1 /18

Step-by-step explanation:

Sum Of Zeroes -> 1/6 + (-1/3)

=1/6 - 1/3

Taking the LCM

(1-2) /6

= -1/6

Product Of Zeroes -> 1/6*(-1/3)

= -1/18

According To rule :

The equation is in the form

x^2 - sx + p ( s is sum of zeroes and p is product)

x^2 - (-1/6) x+ (-1/18)

x^2 + 1/6*x -1/18

Answer 2

Answer:

x^2 +1/6x -1/18

Step-by-step explanation:

this is the answer of the given question