Question

how many atoms of each type are present in 143g of washing soda ​

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Answer 1

Hi there,

◇ Given:

▪ Washing soda formula is Na2CO3

▪ Na atomic mass is 23

▪ C atomic mass is 12

▪ O atomic mass is 16

▪ Molar mass of washing soda is 106g

▪Sample mass is 143 g

▪NA avogadro's no = 6.02×10^23

◇ Number of moles

¤ n= ms÷ Mwt = 143÷106 = 1.35 mol

◇ Nuber of molecules

¤Nu = n× NA = 1.35×6.02×10^23

▪ 8.1213×10^23 molecule

♤ Each molecule have 2 sodium atom

●Number of Na atoms are

8.1213×10^23×2= 1.624×10^24 atom

♤Each molecule have 1 atom carbon

●Number of C atom is

8.1213×10^23 atoms

♤Each molecule have 3 oxygen atoms

●Number of O atoms are

8.1213×10^23×3= 2.436×10^24 atoms

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Answer 2

Answer:

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