Question

Find the qudratic polynomia sum of whose zeroes is o and product is 12. Hence find the zeroes of the polynomial

Answer 1

Hey there !!

we are given ,

$\alpha + \beta = 0 \\ and \: \alpha \beta = 12$
we know , that

$f(x) \: = k( {x}^{2} - ( \alpha + \beta )x + \alpha \beta ) \\ \\ = {x}^{2} - 0x + 12 \\ \\ = > {x}^{2} + 12$
Hope this would help u !!

Answer 2

Answer:

Hey there !!

we are given ,

\begin{gathered} \alpha + \beta = 0 \\ and \: \alpha \beta = 12\end{gathered}

α+β=0

andαβ=12

we know , that

\begin{gathered}f(x) \: = k( {x}^{2} - ( \alpha + \beta )x + \alpha \beta ) \\ \\ = {x}^{2} - 0x + 12 \\ \\ = > {x}^{2} + 12 \end{gathered}

f(x)=k(x

2

−(α+β)x+αβ)

=x

2

−0x+12

=>x

2

+12

Hope this would help u !!