Question

find the quotient and reminder when (6a²-7a-5) is divided by (2a-1)
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Answer 1

Answer:

(3a-5)

Step-by-step explanation:

(6a²-7a-5) is a quadratic equation. It is first solved by factorization

This resulted in $6a^{2} - 3a + 10a - 5 = 0$

Then when further factorized $\frac{3a (2a - 1) + 5 (2a - 1)}{(2a - 1}$ then, $\frac{(3a-5) (2a-1)}{(2a-1)}$

When reduced or simplified you fully cancel out (2a-1) and you are left with (3a-5).