find the radius of a circle in which a chord of length 20cm is at a distance of 80cm from the centre .
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Let AB be the chord of length 30 cm Given that distance from centre to the chord AB is OC = 8 cm OC⊥AB Þ AC = CB[Since perpendicular drawn from centre of the circle bisects the chord] ∴ AC = CB = 15 cm In right ΔOCA, OA2 = AC2 + OC2 = 152 + 82 = 225 + 64 = 289 ⇒ AC = 17 cm Thus the radius of the circle is 17 cm.
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bro ye chord ka distance chord k centre s h kya
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