Find the radius of the base of a right circular cylinder whose curved surface area is 2/3 of the sum of the surface areas of two circular faces.the height of the cylinder is given to be 15 cm
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CSA=2/3×[2(pi×r²)]
2pi×r×h=2/3×[2(pi×r²)]
3×2pi×r×h=2×[2(pi×r²)]
3×2pi×r×h=2×2pi×r²
3×r×h=2r²
r×3×15=2r²
(3×15)/2=r²/r
45/2=r
r=22.5cm
Hence radius of the cylinder is 22.5cm
2pi×r×h=2/3×[2(pi×r²)]
3×2pi×r×h=2×[2(pi×r²)]
3×2pi×r×h=2×2pi×r²
3×r×h=2r²
r×3×15=2r²
(3×15)/2=r²/r
45/2=r
r=22.5cm
Hence radius of the cylinder is 22.5cm
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