Math, asked by siddharthbari, 1 year ago

Find the rate of interest when ₹ 800 fetches rupees 130 as simple interest in 2 year 6 month

Answers

Answered by yousufsami27
0

Find the simple interest on Rs 8600 from 18th October, 2006 to13th March, 2007 at 8% per annum. Also, find the amount.

Ans.

Period 18th Oct. 2006 to 13th March 2007= (13 + 30 + 31 + 31 + 28 + 13) days= 146 days

14623655

= =

yearsNow, Simple interest =

P×R×T100

= Rs 8600821005

× ×=×

Rs13765= Rs 275.20Hence, amount = P + S. I. = Rs 8600 + Rs 275.20 = Rs 8875.20

2.

Ashish lent Rs 10500 to Sunidhi at 7% per annum simple interest.After 5 years, Sunidhi discharged the debt by giving a watch andRs 13000 in cash. What is the value of the watch ?

Ans.

P = 10500,

R = 7% p.a., T = 5 yearsNow,S.I.=

P×R×T100

S. I.= 1050075100

× ×

= Rs 3675

Amount = P + S. I. = Rs 10500 + Rs 3675 = Rs 14175Amount given in cash = Rs13000Thus, balance to be paid = Rs 14175 – 13000 = Rs 1175Hence, value of watch = Rs 117

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