Question

find the ratio in which P( 4 ,m) divided in the line segment joining the point A (2 ,3 )and b( 6, - 3 )find the m​

Answer 1

Answer:

Let

P(4, m) = (x, y)

A(2, 3) = (x1 , y1)

B(6, -3) = (x2, y2)

By using section formula in this points,

Let the ratio in which P divide the line segment A and B be = k : 1

Therefore,

x = k x2 + x1 (1) / k + 1

=> 4 = 6k + 2 /k + 1

=> 4k + 4 = 6k + 2

=> 2k = 2

=.> k = 1

So, the ratio = 1 : 1

Now,

y = k (y2) + 1(y1) / k + 1

=> m = -3 + 3 /1 + 1

=> m = 0/2

m = 0

HOPE THAT IT WAS HELPFUL!!!!

MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!

Answer 2

Answer:

i hv taken m as M ...........the other m's are in the section formula

(m1x2+m2x1/m1+m2)=4           (m1y2+m2y1/m1+m2)=M

6m1+2m2/mi+m2=4                 3m1+ - 3m1/m1+m2+M

6m1+2m2=4m1+4m2                3(1) - 3(1)=2M

6m1-4m1=4m2-2m2                           0=2M

2m1=2m2                                          M=0

m1/m2=1/1

hope it helps