find the ratio in which P( 4 ,m) divided in the line segment joining the point A (2 ,3 )and b( 6, - 3 )find the m
Answers
Answer:
Let
P(4, m) = (x, y)
A(2, 3) = (x1 , y1)
B(6, -3) = (x2, y2)
By using section formula in this points,
Let the ratio in which P divide the line segment A and B be = k : 1
Therefore,
x = k x2 + x1 (1) / k + 1
=> 4 = 6k + 2 /k + 1
=> 4k + 4 = 6k + 2
=> 2k = 2
=.> k = 1
So, the ratio = 1 : 1
Now,
y = k (y2) + 1(y1) / k + 1
=> m = -3 + 3 /1 + 1
=> m = 0/2
m = 0
HOPE THAT IT WAS HELPFUL!!!!
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Answer:
i hv taken m as M ...........the other m's are in the section formula
(m1x2+m2x1/m1+m2)=4 (m1y2+m2y1/m1+m2)=M
6m1+2m2/mi+m2=4 3m1+ - 3m1/m1+m2+M
6m1+2m2=4m1+4m2 3(1) - 3(1)=2M
6m1-4m1=4m2-2m2 0=2M
2m1=2m2 M=0
m1/m2=1/1
hope it helps