Question

find the relation between sinA,cosA and tanA​

Answer 1

Answer:

tanA= sinA/cosA

can be the relation

Answer 2

The relation between sinA, cosA and tanA is tanA = sinA/cosA.

For a right-angled triangle with the height(l), base (b), and hypotenuse (h), the trigonometric ratios are applied as follows for angle A with the base side :

              $sinA = \frac{l}{h}$     [ Height / Hypotenuse ]

              $cosA = \frac{b}{h}$     [ Base / Hypotenuse ]

              $tanA = \frac{l}{b}$     [ Height / Hypotenuse ]

Now, we want to represent the trigonometric ratio tanA in the form of rations sinA and cosA.

From sinA equation, we get : $l = h * sinA$

From cosA equation, we get : $b = h * cosA$

Using these values in the formula of tanA :

                 $tanA = \frac{l}{b}$

                           $= \frac{(h*sinA)}{(h * cosA)}$

                           $= \frac{hsinA}{hcosA}$

                            $= \frac{sinA}{cosA}$

Trigonometric Ration tan is the division of the trigonometric ratio sin by the ratio cos.

Thus, we get the relation between the three trigonometric ratios as :     tanA = sinA / cosA.

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