Question

find the relation between x and y when p(x, y) is equidistant from the points A(-1,2) and B(2,-1).​

Answer 1

Answer:

Let P(x,y) be equidistance from the points A(1,4) and B(−1,2)

Given:AP=BP

AP

2

=BP

2

By distance formula,

(x−1)

2

+(y−4)

2

=(x+1)

2

+(y−2)

2

⇒x

2

−2x+1+y

2

−8y+16=x

2

+2x+1+y

2

−4y+4

⇒−2x+1−8y+16−2x−1+4y−4=0

⇒−4x−4y+12=0

⇒x+y−3=0 gives the relation between x and y.