Question

Find the remainder obtained p(x) =x cube +1 by x+1

Answer 1

We know,
a^3+b^3 =(a+b)(a^2-ab+b^2)
Using this formula,
P(x)=x^3+1^3=(x+1)(x^2-x+1)
...so if we divide P(x) with x+1, (x^2-x+1) remains

Answer 2

Hey,

Solution :-

The zeros of x+ 1 is ( -1 )
by , remainder theorem ,
when x^3 +1 is divided by -1,
the remainder is -1

=> p (x) = x^3 + 1
=> p (x) = (-1)^3 + 1
=> p (x) = -1 + 1 =0

Thus, the required remainder is 0

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