Question

find the remainder using actual division method
p(x) = 2x cube-9x square
+ x + 15 g(x) = 2x-3​

Answer 1

Step-by-step explanation:

thanks for asking hope you understand thanks

Answer 2

Step-by-step explanation:

$g(x) = 2x - 3 \\ 2x - 3 = 0 \\ 2x = 3 \\ x = \frac{3}{2} \\ \\ p(x) = 2 {x}^{3} - 9 {x}^{2} + x + 15 \\ \\ = 2 \times {( \frac{3}{2}) }^{3} - 9 \times {( \frac{3}{2} )}^{2} + \frac{3}{2} + 15 \\ \\ = 2 \times \frac{27}{8} - 9 \times \frac{9}{4} + \frac{3}{2} + 15 \\ \\ = \frac{27}{4} - \frac{81}{4} + \frac{3}{2} + \frac{15}{1} \\ \\ = \frac{27 - 81 + 6 + 60}{4} \\ \\ = \frac{12}{4} \\ \\ = 3$