find the remainder when 2x2-3x+5is divided by 2x-3does it exactly divided the polynomial?state reason
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Hii There!!!
Let the given polynomial be p(x) : 2x^2-3x+5 and it's divisior be g(x) : 2x-3.
Since, p(x) is divisible by g(x)
So, p(x) = 0
or , 2x - 3 = 0
=) x = 3/2
Now , substitute ( put ) the value of 'x' in p (x)
we get ,
2x^2-3x+5
=> 2( 3/2) ^2 - 3
=> 2 × ( 9/4 ) - 3
=> 9/2 - 3
=> 3/2 ≠ 0
Since, the value is not equal to zero.
Hence, 2x - 3 does not divides the given polynomial p (x) .
____________________
Hope it helps
Let the given polynomial be p(x) : 2x^2-3x+5 and it's divisior be g(x) : 2x-3.
Since, p(x) is divisible by g(x)
So, p(x) = 0
or , 2x - 3 = 0
=) x = 3/2
Now , substitute ( put ) the value of 'x' in p (x)
we get ,
2x^2-3x+5
=> 2( 3/2) ^2 - 3
=> 2 × ( 9/4 ) - 3
=> 9/2 - 3
=> 3/2 ≠ 0
Since, the value is not equal to zero.
Hence, 2x - 3 does not divides the given polynomial p (x) .
____________________
Hope it helps
gorak84:
thanks
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