Question

Find the remainder when 3x3 - 4x2 +7x - 5 is divided by x - 3

Answer 1

Answer:

The remainder is -143 , When divided by (x+3).

Step-by-step explanation:

>f(x)=3x3−4x2+7x−5

If it is divided by (x-3). Then according to remainder theorem , the remainder will be f (3).

= > \: f(3) = 3( {3})^{3} - 4 ({3)}^{2} + 7(3) - 5=>f(3)=3(3)3−4(3)2+7(3)−5

= > \: 3(27) - 4(9) + 21 - 5=>3(27)−4(9)+21−5

=> 81+21-41.

=> 61.

So, The remainder is 61.

If we divide the the polynomial by (x+3).Then according to remainder thereom the remainder will be f (-3).

= > \: f( - 3) = 3 ({ - 3})^{3} - 4 ({ - 3})^{2} + 7( - 3) - 5=>f(−3)=3(−3)3−4(−3)2+7(−3)−5

=> 3 (-27)-4 (9)-27-5.

=> -81-36-27-5

=> -143.

So, The remainder is -143 , When divided by (x+3).

Hope this helps!