Question

find the remainder when (x^3-ax+6-a) is divided by (x-a)

Answer 1

$f(x) = {x}^{3} - a {x}^{2} + 6xa \\ putting \: x = 0 \\ f(a) = {a}^{3} - {a}^{3} + 6 {a}^{2} \\ = 6 {a}^{2} \\ so \: remainder \: is \: 6 {a}^{2}$