Question

find the remainder when x cube + 3 X square + 3 X + 1 is divided by X +pie

Answer 1

Answer:

Remainder = -9.84

Step-by-step explanation:

We use the Remainder theorem which states that if a polynomial p(x) is divided with a linear polynomial x - a then the remainder is given by p(a).

Here p(x) = x³ + 3x² + 3x + 1

and linear polynomial = $x+\pi$

now according to remainder theorem,

$remainder=p(-\pi)$

$=(-\pi)^3+3(-\pi)^2+3(-\pi)+1$

$=-\pi^3+3\pi^2-3\pi+1$

we further solve it by putting value of $\pi$ .i.e, $\pi=\frac{22}{7}$

$remainder=-(\frac{22}{7})^3+3(\frac{22}{7})^2-3(\frac{22}{7})+1$

$remainder=-9.84$

Therefore, Remainder = -9.84

Answer 2

Step-by-step explanation:

p(x) = x+π = 0

= x = - π _________ i equation

=> x^3 + 3X^2 + 3X + 1

(-π) ^3 + 3(-π)^2 + 3(-π) +1

-π^3 + 3π^2 - 3π + 1 Ans.

hope it's help you