Question

answer me this question quick quick

Answer 1

Hope it will help you ......✌✌

Answer 2

Given:

P ≡ (x,y)

A ≡ (6,2)

B ≡ (-2,6)

To prove:

y = 2x

Proof:

It is given that, P is equidistant from A and B.

Thus, PA = PB

Now,

By distance formula,

PA = √ (6 - x)² + (2 - y)²

Thus, (PA)² = (6 - x)² + (2 - y)²

Also,

PB = √ (-2 - x)² + (6 - y)²

Thus, (PB)² = (-2 - x)² + (6 - y)²

But,

PA = PB

This implies, (PA)² = (PB)²

(6 - x)² + (2 - y)² = (-2 - x)² + (6 - y)²

Using the identity (a - b)² = a² + b² - 2ab, we get,

36 + x² - 2(6)(x) + 4 + y² - 2(2)(y) = 4 + x² + 2(2)(x) + 36 + y² - 2(6)(y)

- 12x - 4y = 4x - 12y

-12x - 4x = -12y + 4y

-16x = -8y

8y = 16x

On dividing both sides by 8, we get,

y = 2x

Hence, proved.

Hope it helps!!!