find the remainder when x cube +3x square+3x+1 is divided by x+1
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Solution :-
☆ By remainder theory :-
☆ x + 1 = 0
=> x = -1
Put in p ( x ) :-
● p ( - 1 ) :-
= 3 (-1)^2 + 3 (-1) + 1
= 3 - 3 + 1
= 1
:- r = 1 Ans
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Solution :-
☆ By remainder theory :-
☆ x + 1 = 0
=> x = -1
Put in p ( x ) :-
● p ( - 1 ) :-
= 3 (-1)^2 + 3 (-1) + 1
= 3 - 3 + 1
= 1
:- r = 1 Ans
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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