find the remainder when X square + 60 x - 70 divided by
X - 1
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Answered by
1
using remainder theoram,
X-1 =0
X = 1
f(x)= x^2+60x-70
f(1)= (1)^2+60(1)-70
= 1+60-70
= 61-70
= -9.
hence, remainder is -9.
X-1 =0
X = 1
f(x)= x^2+60x-70
f(1)= (1)^2+60(1)-70
= 1+60-70
= 61-70
= -9.
hence, remainder is -9.
Answered by
0
✴ Hey friends!!✴✴
-------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
▶⏩ We find the remainder by using:-)
=> Factor theorem.
=> Hence, x - 1 is the factor of p(x) = x²+60x-70.
↪➡ x - 1 = 0.
↪➡ x = 1.
→ Put the value of x in p(x).
↪➡ p(x) = x² +60x - 70.
↪➡ p(1) = 1² + 60(1) - 70.
↪➡ p = 1 + 60 - 70.
↪➡ p = - 9.✔✔
✴✴ Hence, the remainder of p(x) is -9.✅✅.
⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
-------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
▶⏩ We find the remainder by using:-)
=> Factor theorem.
=> Hence, x - 1 is the factor of p(x) = x²+60x-70.
↪➡ x - 1 = 0.
↪➡ x = 1.
→ Put the value of x in p(x).
↪➡ p(x) = x² +60x - 70.
↪➡ p(1) = 1² + 60(1) - 70.
↪➡ p = 1 + 60 - 70.
↪➡ p = - 9.✔✔
✴✴ Hence, the remainder of p(x) is -9.✅✅.
⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
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